Ответ : 23.
Решение на фото.
[tex]\displaystyle\bf\\\frac{23Sin17^\circ}{Sin377^\circ } =\frac{23Sin17^\circ}{Sin(360^\circ+17^\circ) } =\frac{23Sin17^\circ}{Sin17^\circ } =23[/tex]
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Ответ : 23.
Решение на фото.
[tex]\displaystyle\bf\\\frac{23Sin17^\circ}{Sin377^\circ } =\frac{23Sin17^\circ}{Sin(360^\circ+17^\circ) } =\frac{23Sin17^\circ}{Sin17^\circ } =23[/tex]