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Kroha19022003
@Kroha19022003
August 2022
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sin3α+sai5α=
cos4α-cos2α=
sin6α-sin2α=
cos7α+cosα=
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cuteeeeeee
Sin3a + sai5a = (3ans + 5a `2 s) i
*(2 как степень)
cos4a - cos2a = 2 a c o s
sin6a - sin2a = 4 a n s i
cos7a + cosa = 8 a c o s
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Answers & Comments
*(2 как степень)
cos4a - cos2a = 2 a c o s
sin6a - sin2a = 4 a n s i
cos7a + cosa = 8 a c o s