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ptxvolIII
@ptxvolIII
July 2022
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cos3L+cos4L+cos5L/sin3L+sin4L+sin5L
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sedinalana
(2сos4LcosL+cos4L)/(2sin4LsosL+sin4L)=
=cos4L(2cosL+1)/sin4L(2cosL+1)=cos4L/sin4L=ctg4L
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Answers & Comments
=cos4L(2cosL+1)/sin4L(2cosL+1)=cos4L/sin4L=ctg4L