Home
О нас
Products
Services
Регистрация
Войти
Поиск
ArbeiT
@ArbeiT
July 2022
1
7
Report
cos3x/(sin3x-2sinx)=tgx
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
mawka75
Cos(3x)/(sin(3x) - 2sin(x)) = tg(x)
(4cos³(x) - 3cos(x))/(3sin(x) - 4sin³(x) - 2sin(x)) = tg(x)
(cos(x)*(4cos²(x) - 3)/(sin(x)*(1 - 4sin²(x))) = tg(x)
cos(x)*(2cos(2x) - 1)/(sin(x)*(2cos(2x) - 1) = tg(x)
ctg(x) = tg(x) --> tg(x) = ±1 --> x = π/4 + πk/2, k - целое.
4 votes
Thanks 3
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "(sin3x-2sinx)=tgx..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
(4cos³(x) - 3cos(x))/(3sin(x) - 4sin³(x) - 2sin(x)) = tg(x)
(cos(x)*(4cos²(x) - 3)/(sin(x)*(1 - 4sin²(x))) = tg(x)
cos(x)*(2cos(2x) - 1)/(sin(x)*(2cos(2x) - 1) = tg(x)
ctg(x) = tg(x) --> tg(x) = ±1 --> x = π/4 + πk/2, k - целое.