sin3x + sinx = 0
3sin²x + 3sinx cosx + 2cos²x = 1
√3 - 2sin x < 0
решите уравнения неравенства
3sin²x + 3sinx cosx + 2cos²x = 1
√3 - 2sin x < 0
решите уравнения неравенства
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Answers & Comments
3sin²x+3sinxcosx+2cos²x-sin²x-cos²x=0
2sin²x+3sinxcosx+cos²x=0 /cos²x≠0
2tg²x+3tgx+1=0
D=9-8=1
a1=(-3-1)/4=-1 tgx=-1⇒x=-π/4+πn
a2=(-3+1)/4=-1/2 tgx=-1/2⇒x=-arctg1/2+πn