ДАМ 60 БАЛЛОВ.
Найти производную функции:
1)y= 5^2x/sin3x+7
2)y=е^3-2x *cos(3-2x)
Найти производную функции:
1)y= 5^2x/sin3x+7
2)y=е^3-2x *cos(3-2x)
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Answers & Comments
u=5^2x u'=2*5^2x*ln5
v=(sin3x+7) v'=3cos3x
y'=1/v²[u'v-v'u]=1/(sin3x+7)²]2*5^2x*ln5*(sin3x+7) - 3cos3x*5^2x]
2. y=l^(3-2x)*cos (3-2x)
u=l^(3-2x) u'=-2l^(3-2x)lnl
v=cos (3-2x) v'=2sin(3-2x)
y'=u'v+v'u=-2l^(3-2x)lnl*cos (3-2x) + 2sin(3-2x)*l^(3-2x)