]sin3x=\sqrt{2}cosx-sinx
3sin(x) cos^2 (x)-sin^3(x)=\sqrt{2} cos(x)-sin(x)
sin(x)(2 cos(2x)+1)=\sqrt{2} cos(x)-sin(x)
sin(x)+sin(3x)=\sqrt{2} cos(x)
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Answers & Comments
]sin3x=\sqrt{2}cosx-sinx
3sin(x) cos^2 (x)-sin^3(x)=\sqrt{2} cos(x)-sin(x)
sin(x)(2 cos(2x)+1)=\sqrt{2} cos(x)-sin(x)
sin(x)+sin(3x)=\sqrt{2} cos(x)