Home
О нас
Products
Services
Регистрация
Войти
Поиск
Азизаа99
@Азизаа99
August 2022
1
3
Report
sin4x-cos^4x=-sin^4x
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Dимасuk
Verified answer
Sin4x - cos⁴x = -sin⁴x
sin4x = -sin⁴x + cos⁴x
sin4x = (cos²x - sin²x)(cos²x + sin²x)
sin4x = cos²x - sin²x
2sin2xcos2x = cos2x
2sin2xcos2x - cos2x = 0
cos2x(2sin2x - 1) = 0
cos2x = 0
2x = π/2 + 2πn, n ∈ Z
x = π/4 + πn, n ∈ Z
2sin2x = 1
sin2x = 1/2
2x = (-1)ⁿπ/6 + πn, n ∈ Z
x = (-1)ⁿπ/12 + πn/2, n ∈ Z
Ответ: x = π/4 + πn, n ∈ Z; (-1)ⁿπ/12 + πn/2, n ∈ Z.
1 votes
Thanks 1
рекомендуемые вопросы
rarrrrrrrr
August 2022 | 0 Ответы
o chem dolzhny pozabotitsya v pervuyu ochered vzroslye pri organizacionnom vyvoze n
danilarsentev
August 2022 | 0 Ответы
est dva stanka na kotoryh vypuskayut odinakovye zapchasti odin proizvodit a zapcha
myachina8
August 2022 | 0 Ответы
najti po grafiku otnoshenie v3v1 v otvetah napisano 9 no nuzhno reshenie
ydpmn7cn6w
August 2022 | 0 Ответы
Choose the correct preposition: 1.I am fond (out,of,from) literature. 2.where ar...
millermilena658
August 2022 | 0 Ответы
opredelite kak sozdavalas i kto sozdaval arabskoe gosudarstvo v kracii
MrZooM222
August 2022 | 0 Ответы
ch ajtmanov v rasskaze krasnoe yabloko ispolzuet metod rasskaz v rasskaze opi
timobila47
August 2022 | 0 Ответы
kakovo bylo naznachenie kazhdoj iz chastej vizantijskogo hrama pomogite pozhalujsta
ivanyyaremkiv
August 2022 | 0 Ответы
moment. 6....
pozhalujsta8b98a56c0152a07b8f4cbcd89aa2f01e 97513
sarvinozwakirjanova
August 2022 | 0 Ответы
pomogite pozhalusto pzha519d7eb8246a08ab0df06cc59e9dedb 6631
×
Report "sin4x-cos^4x=-sin^4x..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
Sin4x - cos⁴x = -sin⁴xsin4x = -sin⁴x + cos⁴x
sin4x = (cos²x - sin²x)(cos²x + sin²x)
sin4x = cos²x - sin²x
2sin2xcos2x = cos2x
2sin2xcos2x - cos2x = 0
cos2x(2sin2x - 1) = 0
cos2x = 0
2x = π/2 + 2πn, n ∈ Z
x = π/4 + πn, n ∈ Z
2sin2x = 1
sin2x = 1/2
2x = (-1)ⁿπ/6 + πn, n ∈ Z
x = (-1)ⁿπ/12 + πn/2, n ∈ Z
Ответ: x = π/4 + πn, n ∈ Z; (-1)ⁿπ/12 + πn/2, n ∈ Z.