sin4x-sinx=0
спс за решение
sin4x-sinx=02sin(3x/2)cos(5x/2)=0sin3x/2=0 cos(5x/2)=03x/2=пk 5x/2= п/2+пk3x=2пk 5x=п+2пkx=2пk/3 x=п/5 + 2пk/5
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Verified answer
sin4x-sinx=0
2sin(3x/2)cos(5x/2)=0
sin3x/2=0 cos(5x/2)=0
3x/2=пk 5x/2= п/2+пk
3x=2пk 5x=п+2пk
x=2пk/3 x=п/5 + 2пk/5