sin5x+sinx=корень из трёх умножить на cos2x
2sin 3x * cos 2x = sqrt(3)*cos 2x
cos 2x(2sin 3x -sqrt(3))=0
cos 2x = 0;x=pi/4+pi*n/2;
sin 3x = sqrt(3)/2; x = pi/9+2pi*n/3; x= 2pi/9+2pi*n/3
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2sin 3x * cos 2x = sqrt(3)*cos 2x
cos 2x(2sin 3x -sqrt(3))=0
cos 2x = 0;x=pi/4+pi*n/2;
sin 3x = sqrt(3)/2; x = pi/9+2pi*n/3; x= 2pi/9+2pi*n/3