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zhekafedorova1999
@zhekafedorova1999
July 2022
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вычислите: (3cos28°cos34°-3cos62°cos56°)/(sin74°cos46°-cos44°sin16°)
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sedinalana
Verified answer
(3cos28°cos34°-3cos62°cos56°)/(sin74°cos46°-cos44°sin16°)=
=3(cos28cos34-sin28sin34)/(cos16sin44-cos44sin16)=
=3cos(28+34)/sin(44-16)=3cos62/sin28=3sin28/sin28=3
-------------------------------------------------------------------------------------
используем формулы
sin(π/2-a)=cosa
cos(π/2-a)=sina
cosacosb-sinasinb=cos(a=b)
sinacosb-cosasinb=sin(a-b)
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Answers & Comments
Verified answer
(3cos28°cos34°-3cos62°cos56°)/(sin74°cos46°-cos44°sin16°)==3(cos28cos34-sin28sin34)/(cos16sin44-cos44sin16)=
=3cos(28+34)/sin(44-16)=3cos62/sin28=3sin28/sin28=3
-------------------------------------------------------------------------------------
используем формулы
sin(π/2-a)=cosa
cos(π/2-a)=sina
cosacosb-sinasinb=cos(a=b)
sinacosb-cosasinb=sin(a-b)