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AlvaroMaybach
@AlvaroMaybach
July 2022
1
22
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помогите решить sin20*sin50*sin70*/sin80*
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kirichekov
Verified answer
Sin20*sin50*sin79/sin80=
0,25
1. sin20*sin70*sin50=sin20*sin(90-20)*sin50=sin20*cos20*sin50=(1/2)*(2sin20cos20)*sin50=0,5/sin40*sin50
2. sin80=sin(2*40)=2sin40*cos40=2sin40*cos(90-50)=2sin40*sin50
3. (0,5*sin40*cos50) / (2sin40*cos50)=0,5/2=0,25
3 votes
Thanks 4
kirichekov
в 1-м действии опечатка, ответ: 0,5*sin40*sin50
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Answers & Comments
Verified answer
Sin20*sin50*sin79/sin80=0,251. sin20*sin70*sin50=sin20*sin(90-20)*sin50=sin20*cos20*sin50=(1/2)*(2sin20cos20)*sin50=0,5/sin40*sin50
2. sin80=sin(2*40)=2sin40*cos40=2sin40*cos(90-50)=2sin40*sin50
3. (0,5*sin40*cos50) / (2sin40*cos50)=0,5/2=0,25