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volochkos
@volochkos
October 2021
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sin^4a-cos^4a)/sina +cosa упростить
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sedinalana
Verified answer
(sin²a-cos²a)(sin²a+cos²a)/(sina+cosa)=1*(sina-cosa)(sina+cosa)/(sina+cosa)=
=sina-cosa
4 votes
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Answers & Comments
Verified answer
(sin²a-cos²a)(sin²a+cos²a)/(sina+cosa)=1*(sina-cosa)(sina+cosa)/(sina+cosa)==sina-cosa