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Lway
@Lway
July 2022
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докажите тождество
1-2sin^2a/sina cosa=tga-ctga
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Armenia2780
(1-2sin²a)/sincosa=(sin²a+cos²a-2sin²a)/
sinacosa =(cos²a-sin²a)/sinacosa=
ctga-tga
1 votes
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Answers & Comments
sinacosa =(cos²a-sin²a)/sinacosa=
ctga-tga