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ulianavitashova
@ulianavitashova
August 2021
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синус 690??
распишите как решать парвильно??
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nickkazakov
Так как синус-функция периодическая с периодом 2π,то sin690 можно представить так: sin690=sin(690-720)=sin(-30)=-sin30=-1/2 720-это 4π
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