October 2021 0 26 Report
Синус угла падения на границу раздела двух сред равен sin⁡α=0,5. Определить синус угла преломления sin⁡β, если показатели преломления первой и второй среды равны соответственно n1=1,2 и n2=1,5. Ответ округлить до десятых
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