a) sin2x + cos2x = -1
b) sin2x / 1+cos2x = 0
c) cos(квадрат)х -cosx / 1 - sinx = 0
e) cos3x - cosx / sinx = 0
a) sin2x + cos2x = -1
b) sin2x / 1+cos2x = 0
c) cos(квадрат)х -cosx / 1 - sinx = 0
e) cos3x - cosx / sinx = 0
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Answers & Comments
Ответ: (1-cos2x-sinx)/(cosx-sin2x)= 1-(cos^2x-sin^2x)-sinx/ cosx-2sinxcosx=1-cos^2x+sin^2x-sinx/cosx(1-2sinx)= -sin^2x+sin^2x-sinx/cosx(1-2sinx)= sinx/cosx(1-2sinx), где cos^2x+sin^2x- основное тригонометрическое тождество.