(1+cosx)((1/sinx)-1)=0
sinx≠0
x≠πn
cosx=-1
x=π+2πn
1-sinx=0
sinx=1
x=π/2+2πк
Ответx=π+2πn ;x=π/2+2πк
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sinx≠0
x≠πn
cosx=-1
x=π+2πn
1-sinx=0
sinx=1
x=π/2+2πк
Ответx=π+2πn ;x=π/2+2πк