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zhenya2209
@zhenya2209
August 2022
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sinx - cosx= -1
Можно с вложением? И подробным решением?
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sedinalana
Verified answer
2sinx/2cosx/2-cos²x/2+sin²x/2+sin²x/2+cos²x/2=0
2sinx/2cosx/2+2sin²x/2=0
2sinx/2*(cosx/2 +sinx/2)=0
sinx/2=0⇒x/2=πk⇒x=2πk,k∈z
cosx/2+sinx/2=0/cosx/2
1+tgx/2=0
tgx/2=-1
x/2=-π/4+πn⇒x=-π/2+2πn,n∈z
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zhenya2209
в ответе ещё просто 2Пn
zhenya2209
извиняюсь, не посмотрел
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Answers & Comments
Verified answer
2sinx/2cosx/2-cos²x/2+sin²x/2+sin²x/2+cos²x/2=02sinx/2cosx/2+2sin²x/2=0
2sinx/2*(cosx/2 +sinx/2)=0
sinx/2=0⇒x/2=πk⇒x=2πk,k∈z
cosx/2+sinx/2=0/cosx/2
1+tgx/2=0
tgx/2=-1
x/2=-π/4+πn⇒x=-π/2+2πn,n∈z