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Alegosa
@Alegosa
August 2022
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Помогите доказать тождество, пожалуйста
(1-2sin^2x)/(cosx+sinx)+(1-2cos^2x)/(sinx+cosx)=2cosx
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khkhara
...((sinx-cosx)*(1-2sinx^2)+(cosx+sinx)*(1-2cosx^2))/((cosx+sinx)*(sinx-cosx))=
=(2cosxsinx^2-2cosx^3)/((cosx+sinx)*(sinx-cosx))=(2cosx(sinx-cosx)*(sinx+cosx))/((cosx+sinx)*(sinx-cosx)=2cosx
2cosx=2cosx
2 votes
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Answers & Comments
=(2cosxsinx^2-2cosx^3)/((cosx+sinx)*(sinx-cosx))=(2cosx(sinx-cosx)*(sinx+cosx))/((cosx+sinx)*(sinx-cosx)=2cosx
2cosx=2cosx