система 2 уравнений 2x+y=4 4x^2+y^2=40. Created by vetalmoroz. algebra-ru

2x+y=44+=40y=4-2x4+=40y=4-2x4+16-16x+4=40y=4-2xy=4-2xy=4-2xx=-1, x=3x=-1 y=6x=3 y=-2

система 2 уравнений 2x+y=4 4x^2+y^2=40...

August 2022 1 8 Report

система 2 уравнений 2x+y=4 4x^2+y^2=40

Answers & Comments

buego94 2x+y=4
4 $x^{2}$ + $y^{2}$ =40

y=4-2x
4 $x^{2}$ + $(4-2x)^{2}$ =40

y=4-2x
4 $x^{2}$ +16-16x+4 $x^{2}$ =40

y=4-2x
$8 x^{2} -16x-24=0$

y=4-2x
$x^{2} -2x-3=0$

y=4-2x
x=-1, x=3

x=-1 y=6
x=3 y=-2

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