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istegnisheva
@istegnisheva
July 2022
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Система х+у=2, 2х²-ху=65
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miki68
Х=2-у х=2-у х=2-у
2(2-у)²-(2-у)у=65 2(4-4у+у²)-(2у-у²)=65 8-8у+2у²-2у+у²=65
--------------------------------------------------------------------------------------
х=2-у
3у²-10у-57=0
D=100+684=784=28²
у1=(10+28)/6=6 1/3 х1=2-6 1/3=-4 1/3
у2=(10-28)/6=3 х2=2-3=-1
Ответ:(-4 1/3;6 1/3),(-1;3)
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2(2-у)²-(2-у)у=65 2(4-4у+у²)-(2у-у²)=65 8-8у+2у²-2у+у²=65
--------------------------------------------------------------------------------------
х=2-у
3у²-10у-57=0
D=100+684=784=28²
у1=(10+28)/6=6 1/3 х1=2-6 1/3=-4 1/3
у2=(10-28)/6=3 х2=2-3=-1
Ответ:(-4 1/3;6 1/3),(-1;3)