Ответ:
(y+5)^2-3y=13
y^2+10y+25-3y=13
y^2 +10y+25-3y-13=0
y^2+7y+12=0
D=49-48=1
y1=(-7-1):2= - 8:2= - 4
y2=(-7+1):2= - 6:2=-3
x1=-4+5=1
x2=-3+5=2
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Ответ:
(y+5)^2-3y=13
y^2+10y+25-3y=13
y^2 +10y+25-3y-13=0
y^2+7y+12=0
D=49-48=1
y1=(-7-1):2= - 8:2= - 4
y2=(-7+1):2= - 6:2=-3
x1=-4+5=1
x2=-3+5=2