Home
О нас
Products
Services
Регистрация
Войти
Поиск
Соловей98
@Соловей98
July 2022
1
11
Report
Система уравнений:
x^3-y^3=7
x^3-y^3=9-x^2y+xy^2
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms of service
You must agree before submitting.
Send
Answers & Comments
Denik777
Verified answer
(x-y)(x²+xy+y²)=7
7=9-xy(x-y)
(x-y)((x-y)²+3xy)=7
xy(x-y)=2
Обозначим xy=t, тогда x-y=2/t. Значит
(2/t)·(4/t²+3t)=7
2(4+3t³)=7t³
8+6t³=7t³
t³=8, t=2, откуда
xy=2, x-y=1
(y+1)y=2
y²+y-2=0
y1=-2; y2=1
x1=-1; x2=2
Ответ: (-1;-2), (2;1)
7 votes
Thanks 7
Соловей98
Спасибо огромное! Думала, так и не пойму, как делать. Сейчас разобралась, еще раз спасибо)
Denik777
на здоровье :)
×
Report "Система уравнений: x^3-y^3=7 x^3-y^3=9-x^2y+xy^2..."
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
О нас
Политика конфиденциальности
Правила и условия
Copyright
Контакты
Helpful Social
Get monthly updates
Submit
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
(x-y)(x²+xy+y²)=77=9-xy(x-y)
(x-y)((x-y)²+3xy)=7
xy(x-y)=2
Обозначим xy=t, тогда x-y=2/t. Значит
(2/t)·(4/t²+3t)=7
2(4+3t³)=7t³
8+6t³=7t³
t³=8, t=2, откуда
xy=2, x-y=1
(y+1)y=2
y²+y-2=0
y1=-2; y2=1
x1=-1; x2=2
Ответ: (-1;-2), (2;1)