n(Ba(OH)2) = C*V = 0.1*0.5 = 0.05 моль
m(Ba(OH)2) = n*M = 0.05*171 = 8.55 г
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n(Ba(OH)2) = C*V = 0.1*0.5 = 0.05 моль
m(Ba(OH)2) = n*M = 0.05*171 = 8.55 г