Ответ:
4 Li + O2 -> 2 Li2O
2 Mg + O2 -> 2 MgO
4 P + 5 O2 -> 2 P2O5
Задача
Mr(H2SO4) = 1*2 + 32 + 16*4 = 98
W(H) = Ar(H) * n / Mr(H2SO4) *100% = 1 * 2 / 98 *100% = 2%
W(S) = Ar(S) * n / Mr(H2SO4) *100% = 32 *1 / 98 *100% =33%
W(O) = Ar(O) * n / Mr(H2SO4) *100% = 16*4/ 98 *100% = 65%
Объяснение:
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Answers & Comments
Ответ:
4 Li + O2 -> 2 Li2O
2 Mg + O2 -> 2 MgO
4 P + 5 O2 -> 2 P2O5
Задача
Mr(H2SO4) = 1*2 + 32 + 16*4 = 98
W(H) = Ar(H) * n / Mr(H2SO4) *100% = 1 * 2 / 98 *100% = 2%
W(S) = Ar(S) * n / Mr(H2SO4) *100% = 32 *1 / 98 *100% =33%
W(O) = Ar(O) * n / Mr(H2SO4) *100% = 16*4/ 98 *100% = 65%
Объяснение: