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missandronova2
@missandronova2
August 2021
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Сколько 2 н раствора HCl потребуется для приготовления 150 см3 0,15 н раствора
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udodovi
150см3=0,15л
n=c*V=0.15л*0.15н=0.0225моль
V=n/c=0.0225/2=0.01125л
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Answers & Comments
n=c*V=0.15л*0.15н=0.0225моль
V=n/c=0.0225/2=0.01125л