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muniraG
@muniraG
October 2021
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сколько атомов азота содержит 5 моль нитрата серебра
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хихимик
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AgNO3 N(N) = 5* 6,02*10^23 = 3,01*10^24 атомов
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Verified answer
AgNO3 N(N) = 5* 6,02*10^23 = 3,01*10^24 атомов