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Salomon9702
@Salomon9702
July 2022
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Сколько г О2 нужно для получения 240г MgO?
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WannaMath
Ответ на фотографии.
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Alexei78
Дано
m(MgO)=240 g
------------------
m(O2)-?
2Mg+O2-->2MgO
M(MgO)=40 g/mol
n(MgO)=m/M=240/40=6 mol
n(O2)=n(MgO)/2=3 mol
M(O2)=32 g/mol
m(O2)=n*M=3*32 =96 g
ответ 96 г
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Answers & Comments
m(MgO)=240 g
------------------
m(O2)-?
2Mg+O2-->2MgO
M(MgO)=40 g/mol
n(MgO)=m/M=240/40=6 mol
n(O2)=n(MgO)/2=3 mol
M(O2)=32 g/mol
m(O2)=n*M=3*32 =96 g
ответ 96 г