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KOMIL360
@KOMIL360
August 2022
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сколько грамм бензола можно получить из 112 л метана? Практический выход 80%
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staaars
22.4*112/44.8=56
56*22.4/67.2=18.67
18.67*80/100=14.9 л
1 votes
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Answers & Comments
56*22.4/67.2=18.67
18.67*80/100=14.9 л