Ответ:2Al+Fe2O3=Al2O3+2Fe
n(Al)=108/27=4моль
n(Fe2O3)=160/160=1моль
m(Al2O3)=1*102=102г
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Ответ:2Al+Fe2O3=Al2O3+2Fe
n(Al)=108/27=4моль
n(Fe2O3)=160/160=1моль
m(Al2O3)=1*102=102г