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sss484
@sss484
March 2022
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Сколько граммов гашеной извести Ca(OH)2 можно получить из 5,88г. негашеной извести CaO,содержащий 5% примесей?
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ravshan000111
M(CaO)=5.88*(100%-5%)/100%=5.586г
CaO+H2O=Ca(OH)2
5.586/56=x/74
x=7.381=7.4г
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sss484
Спасибо!
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Answers & Comments
CaO+H2O=Ca(OH)2
5.586/56=x/74
x=7.381=7.4г