Ответ:

дано

m(C2H5OH) = 46 g

m(K) = 46 g

η(H2) = 80%

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V(H2) - ?

M(C2H5OH) = 46 g/mol

n(C2H5OH) = m/M = 46 / 46 = 1 mol

M(K) = 39 g/mol

n(K) = m/M = 46 / 39 = 1.2 mol

n(C2H5OH) < n(K)

2n(C2H5OH) = n(H2)

2C2H5OH+2K-->2C2H5OK+H2

n(H2) = 1 / 2 = 0.5 mol

V теор (H2) = n*Vm = 0.5 * 22.4 = 11.2 L

V прак (H2) = 11.2 * 80% / 100% = 8.96 L

ответ 8.98 л

Объяснение: