2H3PO4 + 3Mg = Mg3(PO4)2 + 3H2
m(H3PO4)=80 g
n(H3PO4)= 0.816 mol
n(H2)=1.224 mol
V(H2)=27.418 л
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2H3PO4 + 3Mg = Mg3(PO4)2 + 3H2
m(H3PO4)=80 g
n(H3PO4)= 0.816 mol
n(H2)=1.224 mol
V(H2)=27.418 л