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gorkunenko99
@gorkunenko99
April 2021
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Сколько моль углекислого газа занимают объем 5,6 л
(н.у)?
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saliva
N(CO2)=V/Vm= 5,6 / 22,4 = 0,25 моль
1 votes
Thanks 2
всемприветики
N= V/Vm , Vm= 22.4 дм3/моль
n=5.6/ 22.4=0.25 моль
0 votes
Thanks 1
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Answers & Comments
n=5.6/ 22.4=0.25 моль