n(NaHCO3) = m/M = 3/84 ≈ 0.0357 моль
N(NaHCO3) = n*Na = 0.0357*6.02*10^23 ≈ 0.215*10^23 молекул
Copyright © 2025 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
n(NaHCO3) = m/M = 3/84 ≈ 0.0357 моль
N(NaHCO3) = n*Na = 0.0357*6.02*10^23 ≈ 0.215*10^23 молекул