M(Ca(OH)2)=74г/моль
n(Ca(OH)2)=11/74=0,15моль
N(Ca(OH)2)=0,15*6,02*10²³=0,903*10²³молекул
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
Verified answer
M(Ca(OH)2)=74г/моль
n(Ca(OH)2)=11/74=0,15моль
N(Ca(OH)2)=0,15*6,02*10²³=0,903*10²³молекул