V(PH3) = 112 л
n(PH3) = 112/22.4 = 5 моль
N(PH3) = 5 * 6.02 * 10²³ = 31 * 10²³ молекул
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V(PH3) = 112 л
n(PH3) = 112/22.4 = 5 моль
N(PH3) = 5 * 6.02 * 10²³ = 31 * 10²³ молекул