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KirikoJapan
@KirikoJapan
July 2022
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Сколько различных значений x, при которых верно равенство: 2x(x+5)(7−3x)(x−4)=0?
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MizoriesKun
Ответ
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2 votes
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amin07am
Verified answer
2x(x+5)(7−3x)(x−4)=0
2x=0
x=0
(x+5)=0
х=- 5
(7−3x)=0
х=7/3=2 1/3
(x−4)=0
х=4
итак 4 ответа
1 votes
Thanks 1
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Answers & Comments
@#[email protected]#$##$##$##$#$
Verified answer
2x(x+5)(7−3x)(x−4)=02x=0 x=0
(x+5)=0 х=- 5
(7−3x)=0 х=7/3=2 1/3
(x−4)=0 х=4
итак 4 ответа