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SpringTrap673Madara
@SpringTrap673Madara
August 2021
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Сколько % соляной кислоты понадобится для реакции с 0,65 г цинка
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mariyasamorods
Решение Zn+2HCl=>ZnCl2+H2 65г--73 г 0,65 г--х г х=0,73 г m(p-paHCl)=0,73/0,01=73 г
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