Объяснение:
BaJ2+2AgNO3=2AgJ+Ba(NO3)2
Mr(AgJ)=108+127=235 г/моль
n(AgJ)=m/Mr=,1.57/235=0.00668моль
n(AgJ) =n(AgNO3)=0.00668моль
Mr(AgNO3) =108+14+16*3=170
m(AgNO3)=n*Mr=0.00668*170=1.1356г
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Объяснение:
BaJ2+2AgNO3=2AgJ+Ba(NO3)2
Mr(AgJ)=108+127=235 г/моль
n(AgJ)=m/Mr=,1.57/235=0.00668моль
n(AgJ) =n(AgNO3)=0.00668моль
Mr(AgNO3) =108+14+16*3=170
m(AgNO3)=n*Mr=0.00668*170=1.1356г