2x²-5x-4=0 | :2
x²-2,5x-2=0
По т. Виета:
p=-2,5; q=-2
x₁+x₂=2,5
x₁x₂=-2
1. 1/x₁²+ 1/x₂²= (x₂²+x₁²)/(x₁x₂)²=((x₂+x₁)²-2x₁x₂)/(x₁x₂)²=(2,5²-2*(-2))/4=2,5625
2.x₁x₂⁴+x₂x₁⁴=x₁x₂(x₂³+x₁³)=x₁x₂(x₁+x₂)(x₁²-x₁x₂+x₂²)=x₁x₂(x₁+x₂)((x₂+x₁)²-3x₁x₂)=-2*2,5*(2,5²-3*(-2))=-5*12,25=-61,25.
Спрашивай, если чего непонятно.
Copyright © 2024 SCHOLAR.TIPS - All rights reserved.
Answers & Comments
2x²-5x-4=0 | :2
x²-2,5x-2=0
По т. Виета:
p=-2,5; q=-2
x₁+x₂=2,5
x₁x₂=-2
1. 1/x₁²+ 1/x₂²= (x₂²+x₁²)/(x₁x₂)²=((x₂+x₁)²-2x₁x₂)/(x₁x₂)²=(2,5²-2*(-2))/4=2,5625
2.x₁x₂⁴+x₂x₁⁴=x₁x₂(x₂³+x₁³)=x₁x₂(x₁+x₂)(x₁²-x₁x₂+x₂²)=x₁x₂(x₁+x₂)((x₂+x₁)²-3x₁x₂)=-2*2,5*(2,5²-3*(-2))=-5*12,25=-61,25.
Спрашивай, если чего непонятно.