Смешали 120 граммов 40%- го 280 граммов 10%- го раствора азотной кислоты. Определите массовую долю азотной кислоты в полученном растворе.
W(HNO3)=(120*0,4+280*0,1)/(280+120)=0,19(19%).
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W(HNO3)=(120*0,4+280*0,1)/(280+120)=0,19(19%).
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