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q2erty
@q2erty
July 2022
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dnepr1
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1а) Найти производную y = -(1/2)x^5+3e^(-x)-∛(x^7).
y' = -x^4-3e^(-x)-(7x^(4/3))/(2^(2/3)).
1б) y = (7x^2+2sin(2x))².
y' = 4(7x²+2sin(2x))(7x+2cos(2x)).
2a)
2б)
3)
4)Объём шара V = (4/3)πR³.
По условию задания
(4/3)πR³ = 36
π.
Отсюда получаем R= ∛((3V)/4π) = ∛((3*36π)/(4π)) =∛27 = 3.
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Answers & Comments
Verified answer
1а) Найти производную y = -(1/2)x^5+3e^(-x)-∛(x^7).y' = -x^4-3e^(-x)-(7x^(4/3))/(2^(2/3)).
1б) y = (7x^2+2sin(2x))².
y' = 4(7x²+2sin(2x))(7x+2cos(2x)).
2a)
2б)
3)
4)Объём шара V = (4/3)πR³.
По условию задания (4/3)πR³ = 36π.
Отсюда получаем R= ∛((3V)/4π) = ∛((3*36π)/(4π)) =∛27 = 3.