Ответ:

Объяснение:

Mr(BaSO4) = 137 + 32 + 16 * 4 = 233г/моль

w(Ba) = Ar(Ba) * n /Mr(BaSO4) * 100% = 137/233 * 100% = 58,8%

w(S)= Ar(S) * n /Mr(BaSO4) * 100% = 32/233 * 100% = 13,7%

w(O)= Ar(О) * n /Mr(BaSO4) * 100% = 16 * 4/233 * 100% = 27,5%

Mr(Ca3(PO4)2= 40 * 3 + (31 + 16 * 4)* 2 = 310 г/моль

w(Ca3) = Ar(Сa) * n /Mr(Ca3(PO4)2 * 100% = 40 * 3/310 * 100% = 38,7%

w(P) =  Ar(Р) * n /Mr(Ca3(PO4)2 * 100% = 31 * 2/310 *100% = 20%

w(О) =  Ar(О) * n /Mr(Ca3(PO4)2 * 100% = 16 * 8/310 * 100% = 41,3%