Ответ:
Объяснение:
(18^(n+3)) / (3^2n+5) *2^(n-2)) =
=(2^(n+3) *(3^2)^(n+3) ) / (3^(2n+5) *2^(n-2)) =
=(2^(n+3) *3^(2n+6))/(3^(2n+5) *2^(n-2))=
=2^((n+3)-(n-2)) *3^((2n+6)-(2n+5))=
=2^(n+3-n+2) *3^(2n+6-2n-5)=
=2^5 * 3=32*3=96
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Ответ:
Объяснение:
(18^(n+3)) / (3^2n+5) *2^(n-2)) =
=(2^(n+3) *(3^2)^(n+3) ) / (3^(2n+5) *2^(n-2)) =
=(2^(n+3) *3^(2n+6))/(3^(2n+5) *2^(n-2))=
=2^((n+3)-(n-2)) *3^((2n+6)-(2n+5))=
=2^(n+3-n+2) *3^(2n+6-2n-5)=
=2^5 * 3=32*3=96