Сократите дробь 1)(k+1)! : (k-1)! 2) (n-2)! : n! 3) (2n+1)! : (2n-1)! 4)(3m)! : 2!(3m-2). Created by LENAGAVVA123. algebra-ru

Сократите дробь 1)(k+1)! : (k-1)! 2) (n-2)! : n! 3) (2n+1)! : (2n-1)! 4)(3m)! :...

July 2022 1 9 Report

Сократите дробь
1)(k+1)! : (k-1)!
2) (n-2)! : n!
3) (2n+1)! : (2n-1)!
4)(3m)! : 2!(3m-2)

Answers & Comments

red321 $k!=1*2*3*...*(k-2)(k-1)*k=(k-2)!*(k-1)*k=\\=(k-1)!*k\\\\\\\frac{(k+1)!}{(k-1)!}=\frac{(k-1)!*k*(k+1)}{(k-1)!}=k(k+1)\\\\\frac{(n-2)!}{n!}=\frac{(n-2)!}{(n-2)!*(n-1)*n}=\frac{1}{n(n-1)}\\\\\frac{(2n+1)!}{(2n-1)!}=\frac{(2n-1)!*(2n)*(2n+1)}{(2n-1)!}=2n*(2n+1)\\\\\frac{(3m)!} {2!(3m-2)}=\frac{(3m-3)!*(3m-2)(3m-1)(3m)}{2!(3m-2)}=\frac{(3m-3)!(3m-1)(3m)}{2}$

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