сократите дробь
ac+bx+ax+bc
-----------------
ay+2bx+2ax+by
=a(c+x)+b(x+c)/y(a+b)+2x(a+b)=(a+b)(x+c)/(a+b)(2x+y)=(x+c)/(2x+y)
b(x+c)+a(c+x) =(c+x)(b+a) =c+x
b(2x+y)+a(y+2x) (y+2x)(b+a) y+2x
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Answers & Comments
=a(c+x)+b(x+c)/y(a+b)+2x(a+b)=(a+b)(x+c)/(a+b)(2x+y)=(x+c)/(2x+y)
b(x+c)+a(c+x) =(c+x)(b+a) =c+x
b(2x+y)+a(y+2x) (y+2x)(b+a) y+2x