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ВладимирБ

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Решение смотри в приложении

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sedinalana

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$(9 ^{n-1} +9^n)^3/(3*27 ^{n-2} +27 ^{n-1} )^2=$ $(9 ^{n-1} )^3*(1+9)^3/[(27 ^{n-2} )^2*(3+27)^2]=$ $(3 ^{n-1} )^6*10^3/[(3 ^{n-2} )^6*30^2]=$ $3 ^{6n-6} *10^3/(3 ^{6n-12} *3^2^10^2)=3^6*10/3^2=3^4*10=81*10=810$

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