1. 3a²+5a-2=0
D=b²-4ac=25-4×(-2)×3=25+24=49
a1;2=(-b±√D)/2a=(-5±7)/6.
a1=-2; a2=1/3.
ax²+bx+c=a(x-x1)(x-x2)
3a²+5a-2=3(a+2)(a-1/3)
2. (1-3a)²=9a²-6a+1.
9a²-6a+1=0.
a=1/3
9a²-6a+1=9(a-1/3)²
9(a-1/3)²/3(a+2)(a-1/3)=3(a-1/3)/(a+2)
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Answers & Comments
1. 3a²+5a-2=0
D=b²-4ac=25-4×(-2)×3=25+24=49
a1;2=(-b±√D)/2a=(-5±7)/6.
a1=-2; a2=1/3.
ax²+bx+c=a(x-x1)(x-x2)
3a²+5a-2=3(a+2)(a-1/3)
2. (1-3a)²=9a²-6a+1.
9a²-6a+1=0.
a=1/3
9a²-6a+1=9(a-1/3)²
9(a-1/3)²/3(a+2)(a-1/3)=3(a-1/3)/(a+2)